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A 2 km long broadcast LAN has 107 bps bandwidth and uses CSMA/CD. The signal travels along the wire at 2 × 108 m/s. What is the minimum packet size that can be used on this network?

asked in Concept of layering & LAN technologies (Ethernet) by gate

1 Answer

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RTT = Transmission Time

Transmission Time = Length of packet / Bandwidth
RTT = 2 (d/v) = 2(2000/2×108) 

Therefore to find minimum size of the packet, 
RTT = Length of packet / Bandwidth
Length of packet = RTT x Bandwith
                         = 2(2000/2×108) x 107 = 200bits = 25bytes

Therefore, minimum size of the packet = 25bytes 
answered by gate

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