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Consider the binary relation:

S = {(x, y) | y = x+1 and x, y ∈ {0, 1, 2, ...}}

The reflexive transitive closure of S is

asked in Set Theory & Algebra by gate

1 Answer

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{(x, y) | y ≥ x and x, y ∈ {0, 1, 2, ... }}

answered by gate

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